soal tentang invers....

y(5 - 4x) = 1 + 3x
5y - 4xy = 1 + 3x
5y - 1 = 4xy + 3x
5y - 1 = x(4y + 3)
(5y - 1)/(4y + 3) = x

x = f⁻¹(x)
y= x setelah di inverskan

f⁻¹(x) = (5x - 1)/(4x + 3)

y=1+3×/5-4×
y(5-4×)=1+3×
5y-4×y=1+3×
-4×y-3×=1-5y
×(-4y-3)=1-5y
×=1-5y/-4y-3
f invers (×)=1-5×/-4×-3 atau 5×+1/4×+3