Jika diketahui tan A – tan B = 2 dan tan A .tan B = 1/2,maka tan (A + B ) ????

tan(A+B)=tanA+tanB/(1-tanA.tanB)..
tanA-tanB=2..
tanA.tanB=1/2.. tanA=1/(2tanB)
maka..
(1/(2tanB))-tanB=2
1-2(tanB^2)=4tanB
2(tanB^2)+4tanB-1=0
maka..
tanB=[-4±(24)^1/2]/2(2)
tanB=-1±1/2.[(6)^1/2]
tanA=1/[2.(-1±1/2.[6]^1/2)]=1/[-2±(6)^1/2]=1/2[-2±(-)(6)^1/2]
tanA=-1±(-)1/2.(6)^1/2
tanA+tanB=-2
..
berarti
tan(A+B)=(-2)/(1/2)=-4
Good Luck