persamaan garis melalui titik (-2,3)&tegak lurus dgn garis yg persamaan nya 2x+3y=6

2x + 3y = 6
m1 = -a/b = -2/3
m1 x m2 = -1
-2/3 x m2 = -1
m2 = -1 : (-2/3)
m2 = -1 x (-3/2p)
m2 = 3/2

y - y1 = m2 (x-x2)
y - 3 = 3/2 (x - (-2))
y - 3 = 3/2 ( x + 2)
y - 3 = 3/2x + 6/2
y = 3/2x + 6/2 + 6/2
y = 3/2x + 12/2
2y = 3x + 12