persamaan garis lurus yg melalui titik (-3,5) & tegak lurus dfn garis yg persamaan nya y-8x=16

y-8x=16
y=8x+16
m1=8
m2=-1/8

(-3,5)
y-b = m(x-a)
y-5 = -1/8(x-(-3))
8(y-5)=-1(x+3)
8y-40=-x-3
x+8y=-3+40
x+8y=37