persamaan garis yang melalui (3,2) dan tegak lurus garis x+2y= 4 adalah...

m1=-½
m2=-1/-½
m2=2
x1=3
y1=2
y-y1=m2(x-x1)
y-2=2(x-3)
y-2=2x-6
y=2x-4

x + 2y = 4
2y = -x + 4
y = -1/2x + 4

m' = -1/2

m' + m" = -1
-1/2 + m" = -1
m" = -1 × -2
m" = 2

y = mx + c
2 = 2.3 + c
2 = 6 + c
2 - 6 = c
-4 = c atau
c = -4

y = 2x - 4