Nilai sigma 11 k=8 (2k-9)(k-7) adalah......

jawab
11
Σ  (2k - 9)(k - 7) =
k= 8

uk = (2k - 9)(k - 7)
k = (8,9,10,11)

k = 8 , u8 =  (16-9)(8-7) = 7(1) =7
k = 9 , u9 = (18-9)(9-7) = 9(2) = 18
k = 10 , u10 = (20-9)(10-7) =11(3) = 33
k = 11, u11= (22-9)(11-7) =(13)(4) = 52

Nilai Sigma = jumlah total = 110