jika x2+4px+4=0 mempunyai akar2 xi dan x2. jika xi.x2 kuadrat+x2.x1 kuarat = 32 maka nilai p =

x² + 4px + 4 = 0
a = 1, b = 4p, c = 4

[tex] x_{1} + x_{2} = \frac{-b}{a} = -4p \\ x_{1}.x_{2} = \frac{c}{a} = 4 \\ x_{1}.x_{2}^{2} + x_{2}.x_{1}^{2} = 32 \\ x_1.x_2(x_1 + x_2) = 32 \\ 4(-4p) =32 \\ -16p = 32 \\ p = \frac{32}{-16} = -2[/tex]