tentukan titik potong antara garis x-3y+3=0 dan 3x-y+3=0

eliminasi y
x - 3y + 3 = 0 |×1
3x - y + 3 = 0 |×3
x - 3y + 3 = 0
9x - 3y + 9 = 0
___________-
-8x - 6 = 0
-8x = 6
x = 6 : -8
x = -¾

substitusi x = -¾ ke persamaan x - 3y + 3 = 0
(-¾) - 3y + 3 = 0
3y = 3 - ¾
3y = 12/4 - ¾
3y = 9/4
y = 9/4 : 3
y = ¾

mak titik potongnya (-¾, ¾)