himpunan penyelesaian dari 2log (x^2+2x+1) =2log (2x^2-2)

[tex]2\log\left(x^{2}+2x+1\right)=2\log\left(2x^{2}-2\right) \\ \log\left(x^{2}+2x+1\right)=\log\left(2x^{2}-2\right) \\ x^{2}+2x+1=2x^{2}-2 \\ x^2-2x^2+2x+1+2=0 \\ -x^2+2x+3=0 \\ x^2-2x-3=0 \\ (x+1)(x-3)=0[/tex]

Jadi [tex]x=-1[/tex] atau [tex]x=3[/tex]