Matematika

Pertanyaan

2x+1y+3z =65.000. 5x+2y+2z =120.000. 1x+1y+4z =60.000

2 Jawaban

  • jawabannya ada di foto
    Gambar lampiran jawaban Febyy252
  • 2x + 1y + 3z = 65000. x 2
    5x + 2y + 2z ==120000. x 1

    4x +/2y + 6z = 130 000
    5x + 2y + 2z = 120 000
    _________________ _
    _ 1x + 4z = 10 000

    5x + 2y + 2z = 120 000. x 1
    1x + 1y + 4z = 60 000. x 2

    5x + 2y + 2z = 120 000
    2x + 2y +.8z = 120 000
    __________________ _
    3x _ 6z = 0


    _1x + 4z = 10 000. x 3
    3x _ 6z = 0. x 1

    _3x + 12z = 30
    _ 3x _ 6z =/0
    ___________ _
    18z = 30
    z = 30/18
    z = 5/3
    _1x + 4z = 10 000
    _1x + ( 4 x 5/3) = 10 000
    _ 1x = 10 000 : 20/3
    _1x = 10 000 ! 3/20
    x = 30 000 : 20/_ 1
    x = _ 15 000

    2x + 1y +3z = 65 000
    ( 2 x _ 15 000) + 1y + ( 3 x 5/3) = 65 000
    _ 30 000 + 1y + 5 = 65 000
    1y = 65 000 + 30 000 _ 5
    y = 94995
    x = _ 15 000
    y = 94995
    z = 5/3



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