2x+1y+3z =65.000. 5x+2y+2z =120.000. 1x+1y+4z =60.000
Matematika
eliana24
Pertanyaan
2x+1y+3z =65.000. 5x+2y+2z =120.000. 1x+1y+4z =60.000
2 Jawaban
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1. Jawaban Febyy252
jawabannya ada di foto2. Jawaban hendri2712
2x + 1y + 3z = 65000. x 2
5x + 2y + 2z ==120000. x 1
4x +/2y + 6z = 130 000
5x + 2y + 2z = 120 000
_________________ _
_ 1x + 4z = 10 000
5x + 2y + 2z = 120 000. x 1
1x + 1y + 4z = 60 000. x 2
5x + 2y + 2z = 120 000
2x + 2y +.8z = 120 000
__________________ _
3x _ 6z = 0
_1x + 4z = 10 000. x 3
3x _ 6z = 0. x 1
_3x + 12z = 30
_ 3x _ 6z =/0
___________ _
18z = 30
z = 30/18
z = 5/3
_1x + 4z = 10 000
_1x + ( 4 x 5/3) = 10 000
_ 1x = 10 000 : 20/3
_1x = 10 000 ! 3/20
x = 30 000 : 20/_ 1
x = _ 15 000
2x + 1y +3z = 65 000
( 2 x _ 15 000) + 1y + ( 3 x 5/3) = 65 000
_ 30 000 + 1y + 5 = 65 000
1y = 65 000 + 30 000 _ 5
y = 94995
x = _ 15 000
y = 94995
z = 5/3Pertanyaan Lainnya