diketahui panjang AB=20cm AE=18cm,BE=24cm,dan BC=18cm tentukan tinggi CD

AB seharusnya 30 cm
EC = 6 cm
AE = 18 cm
Misal BD =x
AD = 30-x
CD = t
AC = [tex] \sqrt{6^{2}+18^{2} } = \sqrt{360} [/tex]
(30-x)²+t²=360
x²+t²=324
t²=324-x²
(30-x)²+324-x²=360
900-60x+x²+324-x²=360
1224-60x=360
60x = 864
x= 14,4
t²=324-(14,4)²
t²=324-207.36
t²=116,64
t=10.8 cm