Tentukan nilai √2^x+3 = (1/4)^x+4

[tex] \sqrt{ {2}^{x + 3 } } = { \frac{1}{4} }^{x + 4} \\ {2}^{ \frac{x + 3}{2} } = {2}^{ - 2(x + 4)} \\ \frac{x + 3}{2} = - 2x - 8 \\ x + 3 = - 4x - 16 \\ 5x = - 19 \\ x = - \frac{19}{5} [/tex]