Matematika

Pertanyaan

hitunglah
a.cosec225°
b.sin135°
c.cotan(-120°)
d.secan(-300)

1 Jawaban

  • Kelas 10 Matematika
    Bab Trigonometri Dasar

    a] cosec 225°
    = 1/sin 225°
    = 1/sin (180° + 45°)
    = - 1/sin 45°
    = - 1/(1/√2)
    = - √2

    b] sin 135°
    = sin (180° - 45°)
    = sin 45°
    = 1/2 √2

    c] cotan (-120°)
    = - cotan 120°
    = - 1/tan 120°
    = - 1/(-√3)
    = (1/3) √3

    d] secan (-300°)
    = secan 300°
    = 1/cos 300°
    = 1/(1/2)
    = 2

Pertanyaan Lainnya