hitunglah a.cosec225° b.sin135° c.cotan(-120°) d.secan(-300)
Matematika
ryerikhoooi
Pertanyaan
hitunglah
a.cosec225°
b.sin135°
c.cotan(-120°)
d.secan(-300)
a.cosec225°
b.sin135°
c.cotan(-120°)
d.secan(-300)
1 Jawaban
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1. Jawaban Anonyme
Kelas 10 Matematika
Bab Trigonometri Dasar
a] cosec 225°
= 1/sin 225°
= 1/sin (180° + 45°)
= - 1/sin 45°
= - 1/(1/√2)
= - √2
b] sin 135°
= sin (180° - 45°)
= sin 45°
= 1/2 √2
c] cotan (-120°)
= - cotan 120°
= - 1/tan 120°
= - 1/(-√3)
= (1/3) √3
d] secan (-300°)
= secan 300°
= 1/cos 300°
= 1/(1/2)
= 2